Scandigrad for Co5!

Scandigrad

Scandigrad

TNPer
Hello! I am Scandigrad, and I am seeking YOUR vote for the Council of Five election! As the Deputy Minister of Defense since the creation of the Co5, I have plenty of experience. I have sat in on plenty of cabinet meetings, and believe I have not only the capability, but also the obligation to work for YOU in the Co5! To add to my resume, I was voted "Best Deputy Minister of 2012" in the latest TNP Award Ceremonies. I plan on bringing honor, integrity and transparency to the Council of Five. My sole allegiance is to the North Pacific. I can assure you that a vote for me would bring transparency, and a focus on the North Pacific to the Council of Five!

You've got questions, I've got answers! Fire away!
 
Betting it's a beater, because the rent is too DAYUM HIGH.

Do you think partisan politics has had an influence on the Co5's decision-making?
 
Funkadelia:
Mr. Scandigrad! Mr. Scandigrad! All the voters want to know: What car do you drive?
Click to expand...
GBM is correct. I drive an '01 Toyota Corolla.

GBM: I am very confident that partisan politics have been an influence in the Co5 on multiple levels. First and foremost, the R/D leaning has been a major factor, and has unfortunately spilled over into matters that do not have anything to do with the R/D debate.

As for political parties, there has been some minor political maneuvering, however I do not believe that these political parties have hindered the Co5 discussions thus far.

I welcome open debate between conflicting viewpoints. Debates of that type allow for considering all options from multiple perspectives, and hopefully provide for the best option to be selected. I beg every single party though, to consider who's interests they are considering when they are in a cabinet meeting. As a native to the North Pacific, and one who's only residence resides in the North Pacific, I can assure you that all of my decisions will be for The North Pacific alone.
 
How many people must there be in a room for it to be more likely than not that two of them have the same birthday?
 
Presuming that you mean better than a 50% chance then the answer is 23 people and the reasoning (ignoging leap years) goes :

- Start with one person in a room. Add a second person and the probability that he has a different birthday is 364/365. Add a third and the probability that he has a different birthday to the first two is 363/365. The probability that there are now no duplicate birthdays is (364/365)*(363/365). Add a fourth and the probability that he has a different birthday to the first three is 362/365. The probability that there are now no duplicate birthdays is (364/365)*(363/365)*(362/365). etc. The probability that there are no duplicate birthdays falls below 50% when the 23rd person arrives.
 
Of all the candidates who were asked this same question, you were the first to give a reply that I actually understood. Kudos!
 
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